This WorkKeys Math practice test covers Level 7 of Applied Math. This is the most difficult level of WorkKeys Math, so the questions are very challenging. Some of the topics covered on this test include calculating volumes, solving problems with ratios, and solving proportions that include fractions. They all require multiple steps of logic and calculation. You may use a calculator.
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Question 1 of 5
1. Question
Tina completed \(\frac{3}{8}\) of the project in \(2 \frac{1}{2}\) weeks. If she continues progressing at the same rate, how many more days will she need to bring the project to completion? Round your answer to the nearest whole number.
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Question 2 of 5
2. Question
Compute the volume of the cylinder shown below in cubic inches. Round your answer to the nearest tenth. There are 16.39 cubic centimeters (cm3) in 1 cubic inch (in3).
Volume of a cylinder ≈ 3.14 × (radius)2 × height
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Question 3 of 5
3. Question
GrassLoppers Incorporated has 5 employees dedicated to cutting grass. The fastest employee is able to mow one acre in 30 minutes; the 3 average employees are each able to mow one acre in 45 minutes; and the slowest employee is able to mow one acre in 60 minutes. How many acres can this team of 5 employees mow in one hour?
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Question 4 of 5
4. Question
An online database company offers two plans. Plan A costs $9 per month plus $0.006 per transaction. Plan B costs $39 per month plus $0.002 per transaction. If you anticipate having 12,000 transactions per month, what will be the expected average unit transaction cost (as defined below) if you select the plan that provides the lowest cost for your situation?
\( \text{Average Unit Transaction Cost}\)
\(= \dfrac{\text{Total Cost Per Month}}{\text{Transactions Per Month}}\)
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Question 5 of 5
5. Question
The illustration below shows the dimensions of the existing cone-shaped container. A new cone-shaped container needs to be designed such that its volume is twice that of the existing container’s volume. Its radius will need to be increased to meet the new volume requirement, but the height of the new container will remain the same (12 cm). What will be the radius of the new container? Round to the nearest tenth.
\(V_{\text{cone}} ≈ \dfrac{3.14 × r^2 × h}{3}\)
(Where \(r\) is the radius and \(h\) is the height.)
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